@Richard,

By SIP server, I mean SIP Proxy, something like Kamailio, OpenSER, ...
I'm not using ICE and TURN.


>In this case, if you only use STUN, media will fail.  (I assume "they
cannot hear each other" means RTP isn't going end to end.)  You >need to
use an RTP server (== TURN server).
How does the SIP proxy know whether to use rtpproxy or not ?





On Fri, Mar 1, 2013 at 5:14 AM, Richard Barnes <[email protected]> wrote:

> When you say "SIP server", do you mean a proxy, or something like a B2BUA?
>
> If you use ICE, there shouldn't be any need for the "SIP server" to modify
> the SDP.  The endpoints should be able to exchange and test candidates
> directly.
>
>
>
> On Feb 28, 2013, at 11:57 AM, Khoa Pham <[email protected]> wrote:
>
> > Hi Richard, thanks for the response.
> >
> > When A call B. The INVITE message will go through SIP server. And this
> SIP server can modify the media address in SDP.
> >
> > When both A, B use STUN. The INVITE message SDP contains the media
> address A obtained through STUN, and SIP server does not modify it. So that
> B will then send rtp packet to this address, hence cause no voice
> >
> > But when either A or B use STUN. This SIP server modify the the media
> address to the address of RTP server. This case A can hear B and vice versa
> >
> > Why is that ?
> >
> >
> > On Thu, Feb 28, 2013 at 8:59 PM, Richard Barnes <[email protected]> wrote:
> > Hi Khoa,
> >
> > > Hi, I have Kamailio as SIP server and RTP server. Client is PJSIP.
> > >
> > > I read that STUN is for non-symmetric NAT, and RTP server is for
> symmetric
> > > NAT.
> >
> > You are correct that an "RTP server" (also called a "TURN server") is
> usually necessary in the case of symmetric NAT.  For some illustrations,
> see this slide deck:
> > <
> http://www.viagenie.ca/publications/2008-09-24-astricon-stun-turn-ice.pdf>
> >
> > Your client will have to gather TURN candidates and send them to the
> other side during ICE negotiation.
> >
> >
> > > Supposed A calls B.
> > >
> > > If A, B both use symmetric NAT and STUN, they cannot hear each other
> >
> > In this case, if you only use STUN, media will fail.  (I assume "they
> cannot hear each other" means RTP isn't going end to end.)  You need to use
> an RTP server (== TURN server).
> >
> >
> > > If A or B use non-symmetric NAT and NOT using STUN, they cannot hear
> each
> > > other.
> >
> > In the case of non-symmetric NAT, you still need to use STUN.  NOT using
> STUN will only work if there are no NATs.
> >
> >
> > > I read
> http://tools.ietf.org/id/draft-takeda-symmetric-nat-traversal-00.txt
> > > for Prediction Failure, is that related to this problem ?
> >
> > That is a very old document, and does not look technically sound.  In
> particular, predicting next port numbers will usually not work, because
> NATs can assign port numbers in any order they want.  I would start with
> the ICE RFC, and work from there:
> > <http://tools.ietf.org/html/rfc5245>
> >
> > Good luck!
> >
> > --Richard
> >
> >
> >
> > --
> > Khoa Pham
> > HCMC University of Science
> > Faculty of Information Technology
>
>


-- 
Khoa Pham
HCMC University of Science
Faculty of Information Technology
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