Ken,
You might mention that if one is trying to support a 6 inch pipe, requiring
1/2 inch all thread rod with a trapeze using 3/8 inch all thread rod, as
the 6 inch pipe is moved from the middle of the span, one of the 3/8 ATRs
will begin to be supporting more of the 6 inch pipe load.  At some point,
the 3/8 inch rod will no longer share the load properly leaving one of the
rods trying to support too much of the load.  Even if the section modulus
is correct, I always have the contractor use 1/2 inch ATR to support the
trapeze if they are trying to support 6 inch pipe.

*
*
*Thanks*
*
*
*Rahe Loftin, PE *
*Fire Protection Engineer (AHJ)*
*General Services Administration*
*Region 7 - TX, OK, NM, AR, LA*
*Design & Construction 7PCE*
*
*
*c - 817-371-3102*
*o - 817-978-7299*


On Mon, Jun 3, 2013 at 9:59 AM, ParsleyConsulting <[email protected]
> wrote:

> Whoops, forgot that to get to 1.09 for the required section modulus, you
> first have to divide PL by 4, then by 15,000.  See how easy it is for even
> a smart aleck like me to make a mistake? The answer was correct, but the
> explanation was flawed, that's why my teachers always asked to show the
> work.
>
>     65,696.4divided by 4= 16,421 and that divided by 15,000 = 1.094
>
> Forgetting a step like that got me much lower grades.
> *
>
> PARSLEY CONSULTING
>
> *
>
> Ken Wagoner
>
> 760.745.6181 voice
>
> 760.745.0537 fax
>
> website: www.ParsleyConsulting.com 
> <http://www.ParsleyConsulting.**com<http://www.ParsleyConsulting.com>
> >
>
> On 6/3/2013 7:51 AM, ParsleyConsulting wrote:
>
>> Brad,
>>     Part 1 - Gibberish.  Pure and simple.  The tables in NFPA 13 didn't
>> reduce the "force" and "distance" by half in their calculations.  It simply
>> used the formula to calculate the maximum moment at the point of the load
>> for a simple beam, based on the maximum length of various pipe sizes
>> between hangers.  That's why the figures for 1" and 1-1/4" are based on 12'
>> between hangers.
>> The maximum moment is the "worst case", and was what the committee saw as
>> providing system designers with enough information to allow them to not use
>> trapeze members which would have excessive loads placed on them.
>>     The formula to determine maximum moment is PL/4, with P=weight of
>> pipe being supported in pounds (including 250#), and L=the length of the
>> span of the trapeze in inches. The moment is then divided by the maximum
>> allowable bending stress, which for steel is 15,000.
>>     The resulting equation looks like this:  (PL/4)/15,000 = required
>> section modulus. So, for 15' of 1-1/2" sch 40 pipe, the value of P would
>> equal 15' x 3.61 = 54.15 + 250 = 304.15#.  For an 18' span, the value of L
>> = 216".  Multiply PxL = 65,696.4, and then divide that value by 15,000, and
>> the result is a required section modulus for the worst case location of the
>> load (mid span) of 1.09 in³. That is just slightly less than doubling the
>> value for a 9'-0" span, however using that method would result in a larger
>> required section modulus, so it would work out in the end.
>>     The 4ab/a+b you reference is a method to calculate the equivalent
>> length of the trapeze, in order to reduce the value of "L" in the original
>> equation. Going back to your 18' span, if the load were 3' from one end,
>> and 15' from the opposite end, that results in the equation
>> 4x180x36/180+36, which equals 120", or 10'.  The value of L in the above
>> equation is changed from 216"to 120", reducing the required section
>> modulus. PL/4 now becomes 304.15 x 120 = 36,498which is divided by 4,
>> resulting in 9,124.5, which is further divided by the allowable bending
>> stress of 15,000 for steel, with a final required section modulus of 0.6083
>> in³. Round that up to 0.61, and it matches the value in NFPA 13, Table
>> 9.1.1.7.1(a) (2013).
>> No reduction by half anywhere in those equations.
>> Part 2 - Relatively correct regarding doubling the require section
>> modulus for a 9' span, however as the structural engineers in the room when
>> this table was expanded to include spans up to 16'-0" notedyou can keep
>> increasing the span to the point where the weight of the trapeze itself now
>> becomes an issue in the overall capacity to resist bending, and that sort
>> of calculation was one they were reluctant to provide without a significant
>> amount of additional information.
>> Please note that this is my opinion only, and does not reflect that of
>> the NFPA 13 Hanging and Bracing Committee.
>> *
>>
>> PARSLEY CONSULTING
>>
>> *
>>
>> Ken Wagoner
>>
>> 760.745.6181 voice
>>
>> 760.745.0537 fax
>>
>> website: www.ParsleyConsulting.com 
>> <http://www.ParsleyConsulting.**com<http://www.ParsleyConsulting.com>
>> >
>>
>> On 5/31/2013 7:36 PM, Brad Casterline wrote:
>>
>>> saw an e-mail the other day about 18 foot trapeze spans.
>>>
>>> wished someone had asked me.
>>>
>>> i would have said---either:
>>>
>>> section modulus is moment divided by stress. moment is half the force(lb)
>>> times half the distance(in).
>>>
>>> the force is the weight of the water-filled pipe plus 250. the distance
>>> is
>>> 4ab/a+b.
>>>
>>> the stress is 15,000.
>>>
>>> or: double the required section modulus for a nine foot span.
>>>
>>>
>>> Brad Casterline, NICET IV
>>>
>>> Fire Protection Division
>>>
>>>
>>> FSC, Inc.
>>>
>>> P: 913-722-3473
>>>
>>> [email protected]
>>>
>>> www.fsc-inc.com
>>>
>>>
>>> Engineering Solutions for the Built Environment
>>>
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