Simon's suggestion about the duplicate "name" still holds. Your relation from Stat->ExtraStat currently needs to be one-to-one since you cannot have more than one ExtraStat referencing a single Stat, due to the PK constraint on ExtraStat.name. The error is raising at the point of query() since autoflush is kicking in - use session.flush() to isolate the error.
On Nov 29, 2008, at 12:18 PM, Doug Farrell wrote: > Hi all, > > I'm having a problem with a new instance of a relation conflicting > with > an existing instance. I'm using SA 0.5rc with Sqlite3. Here are my > simplified classes: > > class Stat(sqladb.Base): > __tablename__ = "stats" > name = Column(String(32), primary_key=True) > total = Column(Integer) > created = Column(DateTime, default=datetime.datetime.now()) > updated = Column(DateTime) > states = Column(PickleType, default={}) > extraStats = relation("ExtraStat", backref="stat") > > class ExtraStat(sqladb.Base): > __tablename__ = "extrastats" > name = Column(String(32), ForeignKey("stats.name"), > primary_key=True) > total = Column(Integer) > created = Column(DateTime, default=datetime.datetime.now()) > updated = Column(DateTime) > states = Column(PickleType, default={}) > > The above Stat class has a one-to-many relationship with the ExtraStat > class (which I think I've implemented correctly). Later in the > program I create an in memory data model that has as part of it's > components two > dictionaries that contain Stat instances. Those Stat instances have > relationships to ExtraStat instances. My problem comes in the > following when I'm trying to update the data in those instances/ > tables. > Here is a section of code that throws the exception: > > > > pressName = "press%s" % pressNum > # add new ExtraStat instances as relations > self._addProductStatsPress(productType, pressName) > self._addPressStatsProduct(pressName, productType) > try: > extraStat = session.query(Stat). \ > filter(Stat.name==productType). \ > join("extraStats"). \ > filter(ExtraStat.name==pressName).one() > except: > extraStat = ExtraStat(pressName, ExtraStat.PRESS_TYPE) > self.productStats[productType].extraStats.append(extraStat) > extraStat.states.setdefault(sstate, 0) > extraStat.states[sstate] += 1 > extraStat.updated = now > extraStat = session.merge(extraStat) > try: > extraStat = session.query(Stat). \ > filter(Stat.name==pressName). \ > join("extraStats"). \ > filter(ExtraStat.name==productType).one() <==== > throws exception right here > except: > extraStat = ExtraStat(productType, ExtraStat.PRODUCT_TYPE) > self.pressStats[pressName].extraStats.append(extraStat) > extraStat.states.setdefault(sstate, 0) > extraStat.states[sstate] += 1 > extraStat.updated = now > > The marked area is wear it throws the exception. I'm not sure what to > do here to get past this, any help or ideas would be greatly > appreciated. > > The exact exception is as follows: > Sqlalchemy.orm.exc.FlushError: New instance [EMAIL PROTECTED] With > identity > key (<class '__main__.ExtraStat'>,(u'C',)) conflicts with persistent > instance [EMAIL PROTECTED] > > Thanks! > Doug > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---