Apologies if I'm missing this is the docs somewhere, but I can't figure it out. Suppose I have a many-to-many relationship between A and B, and that I'd like have the various B's that a particular A points to ordered by B.ordinal (i.e. in the examples below, I'd like A.bs to be sorted to B.order). I can't figure out how to do that. I tried the following:
class A(Base): __tablename__ = 'a' id = Column(Integer, primary_key=True) bs = association_proxy("a_to_b", "b", creator=lambda x: A_to_B(b=x)) class B(Base): __tablename__ = 'b' id = Column(Integer, primary_key=True) order = Column(Integer) class A_to_B(Base): a_id = Column(Integer, ForeignKey(str(A.__table__) + ".id"), nullable=False, index=True) b_id = Column(Integer, ForeignKey(str(B.__table__) + ".id"), nullable=False) b = relationship(B, foreign_keys=[b_id]) a = relationship(A, foreign_keys=[a_id], backref=backref("a_to_b", lazy="subquery", cascade="all, delete-orphan", order_by=b.ordinal)) def __init__(self, a=None, b=None): self.a = a self.b = b but get an error message: AttributeError: 'RelationshipProperty' object has no attribute 'ordinal' Is it possible to combine an association_proxy with an order_by clause? Thanks! -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at http://groups.google.com/group/sqlalchemy. For more options, visit https://groups.google.com/groups/opt_out.