Hi Michal
> q.join(ReferenceAuthor, ReferenceAuthor.c.Index == 0)
Ah, of course! Thank you very much!
But... ;)
This Python code
return self.session.query(Reference) \
.filter_by(_mark = False) \
.join(Periodical) \
.join(ReferenceAuthor,
ReferenceAuthor.c.Index==0) \
.join(Person) \
.order_by(Periodical._name) \
.order_by(Person._lastname) \
.all()
The SQL echoed looks ok:
SELECT "Reference"."ID" AS "Reference_ID",
"Reference"."HasLabel" AS "Reference_HasLabel",
"Reference"."PeriodicalID" AS "Reference_PeriodicalID"
FROM "Reference"
JOIN "Periodical"
ON "Periodical"."ID" = "Reference"."PeriodicalID"
JOIN "ReferenceAuthor"
ON "ReferenceAuthor"."Index" = ?
JOIN "Person"
ON "Person"."ID" = "ReferenceAuthor"."PersonID"
WHERE "Reference"."HasLabel" = 0
ORDER BY "Periodical"."Name",
"Person"."LastName"
But result doesn't looks like that it is secondary sorted by first
persons lastname. See as an example one "Periodical._name" (Bmc
Geriatrics) and the first persons lastname of 8 References.
Bmc Geriatrics
Dapp
Tuntland
Hsu
van der Elst
Khatib
Hermans
van Buul
Lichtner
--
Verfassungsbeschwerden gegen Vorratsdatenspeicherung
<https://digitalcourage.de/weg-mit-vds>
Dein Recht zu unterzeichnen!
--
You received this message because you are subscribed to the Google Groups
"sqlalchemy" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to sqlalchemy+unsubscr...@googlegroups.com.
To post to this group, send email to sqlalchemy@googlegroups.com.
Visit this group at https://groups.google.com/group/sqlalchemy.
For more options, visit https://groups.google.com/d/optout.
