> it will generate the same SQL and provide "2" for the bound value > instead of "1".
Why is the expression “func.count(Address.id) > literal_column("2")” not referenced there? > I don't know what SQL you are attempting to render. I would like to get an asterisk instead of the parameters “count_1” and “count_2”. Regards, Markus -- SQLAlchemy - The Python SQL Toolkit and Object Relational Mapper http://www.sqlalchemy.org/ To post example code, please provide an MCVE: Minimal, Complete, and Verifiable Example. See http://stackoverflow.com/help/mcve for a full description. --- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sqlalchemy+unsubscr...@googlegroups.com. To post to this group, send email to sqlalchemy@googlegroups.com. Visit this group at https://groups.google.com/group/sqlalchemy. For more options, visit https://groups.google.com/d/optout.