On 03/01/2019 22:22, Peter da Silva wrote:
Why is the exponent in the low bits, since it forces unnecessary shifts for
integer operations?
That's easy, because the high bits are closer to the barrel shifter, so
it takes less time for the electron to get there![1][2]
Cheers,
Gary B-)
1 - Oh ghod, bit-order arguments, worse than the shell wars and the
editor wars combined!!!
2 - Sarcasm intended, for those who may not be certain.
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