OK, here I am again trying to find out how to create a table
CreateTable() {
create_table = "CREATE TABLE friend (name TEXT, address TEXT, age INT)";
rc = sqlite3_prepare_v2(
db,
create_table.c_str() ,
create_table.length(),
&stmt,
NULL
);
....
rc = sqlite3_step(stmt);
if(rc != SQLITE_DONE) { ... }
/// the output here is 5, meaning SQLITE_NULL. The output should be 3 =
SQLITE3_TEXT
std::cout << sqlite3_column_type(stmt,0) << std::endl;
sqlite3_finalize(stmt);
}
I checked my SQL statement and it is correct, why is SQLite reporting 5 when
it is supposed to be 3?
-----Original Message-----
From: sqlite-users-boun...@sqlite.org
[mailto:sqlite-users-boun...@sqlite.org] On Behalf Of Igor Tandetnik
Sent: Sunday, June 24, 2012 12:55 PM
To: sqlite-users@sqlite.org
Subject: Re: [sqlite] C++ programming - getting data from a table
Arbol One <arbol...@gmail.com> wrote:
> Thank you for the prompt response. Now, using simple std::cout, could
> you show (give an example) of how to display (out streaming) the data
extracted?
sqlite3* db;
sqlite3_open("db", &db);
sqlite_stmt* stmt;
sqlite3_prepare_v2(db, "select name, address, age from friend", -1, &stmt,
NULL);
while (sqlite3_step(stmt) == SQLITE_ROW) {
cout << (char*)sqlite3_column_text(stmt, 0) << ' ' <<
(char*)sqlite3_column_text(stmt, 1) << ' ' <<
sqlite3_column_int(stmt, 2) << endl; }
sqlite3_finalize(stmt);
sqlite3_close(db);
Error handling is left as an exercise for the reader.
--
Igor Tandetnik
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