> By definition, A % B < B. Thus, if B fits into an int (be it 32-bit or
> 16-bit or otherwise), then A % B would too.


I'm not sure this is *strictly* true if negative numbers are involved; e.g.
-4 % -3 = -1.
But it's still true to say it's closer to zero, and thus should always fit
into an int.
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