I didn't see this go through, so I'm sending it again. I got an Alexa spam, so 
maybe that's part of it. 

I ran the following code on my ARM processor:

 double c25 = 0.0;
 c25 += 9.2;
 c25 += 7.9;
 c25 += 0.0;
 c25 += 4.0;
 c25 += 2.6;
 c25 += 1.3;
 double n25 = 25.0;

 double c23 = 0.0;
 c23 += 9.2;
 c23 += 7.8;
 c23 += 0.0;
 c23 += 3.0;
 c23 += 1.3;
 c23 += 1.7;
 double n23 = 23.0;

 double c21 = 0.0;
 c21 += 9.2;
 c21 += 7.9;
 c21 += 0.0;
 c21 += 1.0;
 c21 += 1.3;
 c21 += 1.6;
 double n21 = 21.0;

My debugger shows the following:

C25: 2.5000000000000003E+1 (0x4039000000000001)
N25: 25.0 (0x4039000000000000)
C23: 23.0
N23: 23.0
C21: 2.1000000000000003E+1 (0x4035000000000001)
N21: 21 (0x4035000000000000)

The error is down in the least significant bit.

-----Original Message-----
From: sqlite-users-bounces at mailinglists.sqlite.org 
[mailto:sqlite-users-boun...@mailinglists.sqlite.org] On Behalf Of Jim Callahan
Sent: Friday, October 23, 2015 11:19 AM
To: General Discussion of SQLite Database
Subject: Re: [sqlite] Simple Math Question

Pocket calculators and COBOL used binary coded decimal (bcd) numbers to avoid 
the representation/round off issues. But this meant another entire number type 
(supported with addition, subtraction and having to be type checked in 
functions) in addition to integer and floating point; most found it easier to 
use integers to keep track on pennies...

> On Fri, Oct 23, 2015 at 11:05 AM, Scott Hess <shess at google.com> wrote:
> 
> On Fri, Oct 23, 2015 at 7:39 AM, Dominique Devienne 
> <ddevienne at gmail.com>
> wrote:
> 
>> On Fri, Oct 23, 2015 at 4:16 PM, Rousselot, Richard A < 
>> Richard.A.Rousselot at centurylink.com> wrote:
>>> So I decided to output 1000 digits, because why not?  So now I am 
>>> more perplexed with all these digits showing it is working the 
>>> opposite of
>> how I
>>> expected it.  Why is the second set of equations evaluating to a "yes"
>> when
>>> it is the only one that is obviously NOT equal to the expression???
>> 
>> Indeed, that's puzzling :)
> 
> 
> Just to be clear, though, how floating-point numbers work is breaking 
> your expectations because your expectations are wrong when applied to 
> floating-point numbers.  Internally, they are base-2 scientific 
> notation, so asking for more significant digits in the base-10 
> representation won't help - base-10 fractional numbers cannot always 
> be represented precisely in base-2, ALSO base-2 fractional numbers 
> cannot always be represented precisely in base-10, so it's like a game 
> of telephone where you can end up slightly removed from where you 
> started out, even though it seems like it's a simple round trip.  
> Since each individual digit cannot be represented perfectly, it 
> doesn't matter how many digits of precision you ask for, you'll always 
> be able to find cases where it doesn't line up like you expect.
> 
> Think of it this way: Find an English sentence, and find an English to 
> Japanese translator.  Translate each individual word of the sentence 
> from English to Japanese, then concatenate the results together.  Then 
> translate the entire original sentence to Japanese.  The results will 
> almost never be the same.  Then do the same process translating the 
> Japanese back to English.  Again, the two routes will provide 
> different results, _and_ both of those results will almost certainly 
> not match the original English sentence.  This isn't a reflection of the 
> translator's abilities at all.
> 
> I'm not saying the computer is always right, just that the computer is 
> following a very strict recipe with reproducible results.  I don't 
> mean reproducible like your three examples make logical sense to you, 
> the user, I mean reproducible like my Intel box gives the same results 
> as my AMD box as my ARM box.  If you want to be able to deal with 
> fractional decimal values with high fidelity, you either need to 
> arrange for base-10 representation (slow, because computers have to 
> simulate it), or you have to do your math in shifted fashion (fast, but can 
> be error prone).
> 
> -scott
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