Hank,

Yes, thanks indeed. Your explanation has really helped me visualize what's going on.

It seems that trying to find South or North from the moon isn't a great method, but perhaps Bill's modification would help? Anyway, as a last resort any compass is better than none. I have twice in my life become severely disorientated when hiking. These days I keep a magnetic compass permanently attached my knapsack so that I can't forget to bring it, but on both those occasions I had to resort to using whatever I could see in the sky to try to get my bearings.

It seems that the time measurement idea I set out in my earlier email is a dud. A bearing error of 20+ degrees could result in up to a couple of hours error in the time estimate. Actually, as well, for the sun and moon to both be above the horizon at the same time doesn't happen that much overall.

Steve





On 12/05/2014 12:31 PM, Bill Gottesman wrote:
Thanks, Hank. Very helpful observations. The ecliptic north pole lies in the curve of Draco's (The Serpent) neck. From your explanation, it seems that the line connecting the crescents of the moon should always point approximately to that location, and this should be something easy to test in the night sky. Is there a way to use this information (perhaps the time of year) to help refine finding south by the moon's crescent? -Bill


On Mon, May 12, 2014 at 3:07 AM, Hank de Wit <h.de...@bom.gov.au <mailto:h.de...@bom.gov.au>> wrote:

    HI Steve,

    I think I can answer this one approximately. The maths is also
    beyond me, but we can get an intuitive answer without causing too
    much brain strain.

    The first point to remember is that both the Sun and the Moon
    travel on paths nearly along the Ecliptic. The Sun sits exactly on
    the Ecliptic, and the Moon, deviates plus or minus 5 degrees,
    because it's orbit is inclined by 5 degrees to the Ecliptic. This
    means that that shadow of the terminator between light and dark on
    the moon must be aligned nearly perpendicular to the path of the
    Ecliptic in the sky - they are in the same plane. So the problem
    reduces to the angle that the path of the Ecliptic makes in the sky.

    To reduce variables even more, let's just think about the Moon
    when it is highest in the sky, along the meridian through South
    (North in the SH).

    We need a planisphere to visualise, and I found a nice online one
    here:
    http://drifted.in/planisphere-app/app/index.xhtml

    This planisphere has the Ecliptic marked as a blue line in the
    sky. If you rotate the outer disk to move through the months, and
    imagine the Moon along the Ecliptic and sitting on the north-south
    meridian you can clearly see the tilt of the Ecliptic line, and
    therefore the line through the horns of the Moon if it were
    located at that point. You can see that this line is not directly
    through north for most of the year, and can be either side. The
    biggest deviations are at the two equinoxes. It is pointing south
    (north) at the solstices. I wonder if the amount of maximum
    deviation from due south (north) is plus and minus 23.5 degrees.

    Many regards
    Hank

    -----Original Message-----
    From: sundial [mailto:sundial-boun...@uni-koeln.de
    <mailto:sundial-boun...@uni-koeln.de>] On Behalf Of Steve Lelievre
    Sent: Sunday, 11 May 2014 12:22 AM
    To: sundial@uni-koeln.de <mailto:sundial@uni-koeln.de>
    Subject: Using the moon to find south

    Hi folks,

    Only loosely related to my question just posted, I'm interested to
    know more about a primative navigation method I've read of. The
    idea is that if one projects an imaginary line through the cusps
    of a crescent moon down to the horizon, that gives the approximate
    position of South (or perhaps North depending on your hemisphere).

    How accurate is this position compared to true south? I'm guessing
    it depends on the time of year, phase of moon and latitude - can
    any one supply formulae? Working it out from first principles is
    beyond my math ability.

    I'm thinking that if I can use the moon to find south, I can then
    measure the azimuth of the sun and use that to get time of day...

    Thanks,
    Steve





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