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--- Begin Message ---This is a lot of math for me to digest at once! One sanity check I like to use is setting the azimuth to due south (whether 180° or 0°). In this case, latitude, and declination don't make any difference and the hour angle should be zero. Having written these equations, can you readily see if this sanity check holds true? > On Jul 20, 2024, at 11:50 AM, Steve Lelievre > <steve.lelievre.can...@gmail.com> wrote: > > > On 2024-07-20 7:01 a.m., John Goodman via sundial wrote: >> My ultimate objective is to find the sun's hour angle on a given day, in a >> given location, when it reaches a selected azimuth. > John, here's my attempt. I've never used this result so my calculation needs > checking. > > Cheers, > > Steve > > > > δ is solar declination > > φ is latitude > > ω is hour angle > > γ is azimuth > > > Solar position vector S is >  > so >  > Rearrange: >  > Above equation is of form: >  > Using trig identities: >  where  and  > in which case >  > or >  > or >  > > We have to watch out for quadrant in inverse functions. > > --------------------------------------------------- > https://lists.uni-koeln.de/mailman/listinfo/sundial
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