On Tue, Apr 15, 2008 at 09:08:47AM +0200, Friedrich Hagedorn wrote: > In [27]: f=Lambda(x, exp(x*x)*log(x*x)-x) > In [29]: f(2.0) > Out[29]: -2 + exp(4)*log(4) > > I think this is not the expected behavior, but you can do > > In [30]: f(2.0).evalf() > Out[30]: 73.68910751852562519599736335 > > The advantage from the Lambda() methode is that you can use your > sympy expressions directly. But it is very slow compared to the python > lambda.
Ok. One more way is In [5]: F=lambdify(exp(x*x)*log(x*x)-x, [x]) In [10]: F(2) Out[10]: 73.6891075185 And this ist fast, but dont work with numpy arrays. This topic was discussed in http://groups.google.com/group/sympy/browse_thread/thread/41d4a85323d09fa1# --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to sympy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sympy?hl=en -~----------~----~----~----~------~----~------~--~---
