That seems reasonable since fraction is allowing the expr to rewrite:

>>> 2*e
2*(x + 1)/(x - 1)
>>> fraction(_)
(2*x + 2, x - 1)


On Friday, March 27, 2015 at 4:28:28 AM UTC-5, Paul Royik wrote:
>
> Both fraction and as_numer_denom return (2x+2, sin(x)+1) for expression 
> 2(x+1)/(sin(x)+1), i.e. they rewrite numerator and denominator.
> I suggest simple fix for fraction: substitute last line return 
> Mul(*numer), Mul(*denom) with return Mul(*numer, evaluate=False), 
> Mul(*denom, evaluate=False)
> For as_numer_denom fix seems harder to implement.
>
> Is it possible to change them?
>
>
> On Friday, March 27, 2015 at 1:40:39 AM UTC+2, Aaron Meurer wrote:
>>
>> It looks like fraction takes into account assumptions, but on the 
>> other hand, it doesn't do any rewriting of the expression to combine 
>> sums of fractions (e.g., fraction(1/x + 1/y) gives (1/x + 1/y, 1), 
>> whereas (1/x + 1/y).as_numer_denom() gives (x + y, x*y)). 
>>
>> Aaron Meurer 
>>
>> On Thu, Mar 26, 2015 at 12:09 PM, Paul Royik <distan...@gmail.com> 
>> wrote: 
>> > I used as_numer_denom earlier and now found fraction. 
>> > Is there any difference between them? 
>> > 
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