Isn't this just because the Mul evaluates itself. I don't think it's
actually fraction() that is rewriting things.

Aaron Meurer

On Fri, Mar 27, 2015 at 9:31 AM, Chris Smith <smi...@gmail.com> wrote:
> That seems reasonable since fraction is allowing the expr to rewrite:
>
>>>> 2*e
> 2*(x + 1)/(x - 1)
>>>> fraction(_)
> (2*x + 2, x - 1)
>
>
> On Friday, March 27, 2015 at 4:28:28 AM UTC-5, Paul Royik wrote:
>>
>> Both fraction and as_numer_denom return (2x+2, sin(x)+1) for expression
>> 2(x+1)/(sin(x)+1), i.e. they rewrite numerator and denominator.
>> I suggest simple fix for fraction: substitute last line return
>> Mul(*numer), Mul(*denom) with return Mul(*numer, evaluate=False),
>> Mul(*denom, evaluate=False)
>> For as_numer_denom fix seems harder to implement.
>>
>> Is it possible to change them?
>>
>>
>> On Friday, March 27, 2015 at 1:40:39 AM UTC+2, Aaron Meurer wrote:
>>>
>>> It looks like fraction takes into account assumptions, but on the
>>> other hand, it doesn't do any rewriting of the expression to combine
>>> sums of fractions (e.g., fraction(1/x + 1/y) gives (1/x + 1/y, 1),
>>> whereas (1/x + 1/y).as_numer_denom() gives (x + y, x*y)).
>>>
>>> Aaron Meurer
>>>
>>> On Thu, Mar 26, 2015 at 12:09 PM, Paul Royik <distan...@gmail.com> wrote:
>>> > I used as_numer_denom earlier and now found fraction.
>>> > Is there any difference between them?
>>> >
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