On 9/9/12 9:37 PM, li...@lazygranch.com wrote:
What am I missing here? Vce = Vbe, so the diode connected transistor isn't saturated.
I think it's where the diode is fully conducting, and into the linear part of the V/I curve, not in the square law part any more.
In normal use the LO port is driven hard enough that the mixer is (hopefully) acting as a switch (and RF port is <-10dB relative to the LO)
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