Jim Lux wrote:
On 9/9/12 9:37 PM, li...@lazygranch.com wrote:
What am I missing here? Vce = Vbe, so the diode connected transistor
isn't saturated.
I think it's where the diode is fully conducting, and into the linear
part of the V/I curve, not in the square law part any more.
In normal use the LO port is driven hard enough that the mixer is
(hopefully) acting as a switch (and RF port is <-10dB relative to the LO)
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Not quite, its when the LO input is large enough to switch the diodes
and the RF level is comparable to the LO level..
If the IF output level (for a fixed LO level) is plotted against the RF
input level, the curve exhibits a knee and the IF output level saturates
at a fixed level when the Rf input level is sufficiently large.
At low signal levels the IF output signal level is a proportional to the
RF input level at high Rf input levels the IF output level approaches a
limiting value.
Bruce
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