Hi

My main point is that a +22 dbm (or even 16 dbm) OCXO is a *very* rare item. If 
your 
signal generator is set to +22 dbm … shame on you. If the part can do well over 
+7 to 
+13 dbm, that will cover the vast majority of the 10 MHz oscillators / signal 
sources out there.

Bob 

> On Jan 19, 2018, at 8:51 PM, Bruce Griffiths <bruce.griffi...@xtra.co.nz> 
> wrote:
> 
> Even the modern PICs spec 50mA max input currents.
> Simulation indicates 20mA peak diode currents without the 330 ohm resistors 
> for a 2V pp input, even more for higher input signal levels. If one can 
> guarantee that input is around 1V pp then the extra diodes and resistors 
> aren't required. If its possible that an input of 16dBm or more may be used 
> then the extra diodes and resistors are required. I simulated the circuit for 
> inputs up to +22dBm.
> Current flowing in the IC protection diodes can degrade the timing jitter 
> substantially (tens of picosec for HCMOS).
> 
> Bruce 
>> On 20 January 2018 at 14:34 Bob kb8tq <kb...@n1k.org> wrote:
>> 
>> 
>> Hi
>> 
>> Unless you really beat on the thing for days on end, you can do without the 
>> 330 ohm and 100 ohm
>> resistors (along with the two diodes). Most modern gates have pretty robust 
>> protection diodes. The
>> source impedance is high enough after the transform that the available 
>> current is pretty low. On a
>> NC7SZ125 the negative diode is rated for 50 ma max and the positive diode is 
>> rated for 20 ma
>> 
>> Some math:
>> 
>> If the two 1K’s properly terminate the circuit, you have a 250 ohm source. 
>> (500 ohm load and 500 ohm
>> transformed from the sine input). A 1V overdrive (1/2 V + and 1/2 V -) will 
>> put 2 ma into the diodes on the
>> peaks.  The more likely case is that the negative is hit a bit harder. The 
>> bias is most likely a bit below
>> 1/2 Vcc for best symmetry. 
>> 
>> None of this is to say you *should* hit the diodes. No matter what sort they 
>> are, the performance will 
>> degrade a bit when you do. How much is of course a “that depends”. Most of 
>> us are not driving the
>> gate with a -180 dbc/Hz source and expecting -177 out of the gate.
>> 
>> Bob
>> 
>>> On Jan 19, 2018, at 8:14 PM, Bruce Griffiths <bruce.griffi...@xtra.co.nz> 
>>> wrote:
>>> 
>>> Something like the attached circuit is suitable for  driving the MCU clock 
>>> input directly.
>>> The diodes should be schottky signal diodes like the 1N5711 series. The 
>>> series resistors limit the diode peak current and the CLK input protection 
>>> network current. It should work with inputs from 1V pp to 8Vpp. If SMT 
>>> components were used it should all fit on a DIP compatible daughter board.
>>> 
>>> Bruce
>>>> On 20 January 2018 at 12:37 Bob kb8tq <kb...@n1k.org> wrote:
>>>> 
>>>> 
>>>> Bob
>>>> 
>>>> With a 1V p-p sort of output, a simple matching network will get you into 
>>>> the 4 to 6V p-p range.
>>>> Drive that into a 5V compatible CMOS gate and move on …. If you have a 
>>>> super hot output, put 
>>>> a 3 db pad on it. 
>>>> 
>>>> Bob
>>>> 
>>>>> On Jan 19, 2018, at 5:40 PM, Tom Van Baak <t...@leapsecond.com> wrote:
>>>>> 
>>>>>> Tom
>>>>>> What's the input signal amplitude?
>>>>>> What's the desired output signal (eg 5V CMOS, 3.3V CMOS etc)?
>>>>>> Bruce
>>>>> 
>>>>> It's for a typical 5 or 10 MHz OCXO / Rb / Cs with sinewave output; say, 
>>>>> 1 Vpp. The output should be 3.3 or 5 V depending on what the MCU needs. 
>>>>> It doesn't have to have stunning performance: think breadboard, PIC, 
>>>>> Arduino sort of stuff. I was looking for something in a PDIP-8 package; 
>>>>> the same as all the picDIV or picPET chips I use. That's why older parts 
>>>>> like µA9637 / DS9637 came to mind.
>>>>> 
>>>>> /tvb
>>>>> 
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>>> <PIC_CLK_Network.gif>
>> 

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