Hello,
a little algorithmic question.
I have a list of tuples element, in which the first item is a kind of key. I
need a target list
with only one tuple per key. But the order must be kept -- so that I cannot use
a temp dictionary.
Additionally, in this case the chosen element for a repeted key is the last one
occurring in
source list.
How would you do that?
I used the following method that walks through the list with indexes in
top-down order, and
"marks" items to delete by "None-ing" them. But this a ugly trick imo, and I
find the overall
method to complicated for such a simple task. There shold be a clear one-liner
for that, I guess.
Also, how to practically walk in reverse order in a list without copying it
(e.g. items[::-1]),
especially if i need both indexes and items (couldn't find with enumerate()).
items =
[(1,'a'),(1,'b'),(2,'a'),(3,'a'),(3,'b'),(4,'a'),(5,'a'),(5,'b'),(5,'c')]
keys = []
for index in range(len(items)-1,-1,-1):
key = items[index][0]
if key in keys:
items[index] = None
else:
keys.append(key)
items = [item for item in items if item is not None]
denis
------
la vida e estranya
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