On Fri, Jan 16, 2009 at 9:15 AM, Kent Johnson <ken...@tds.net> wrote:
> On Thu, Jan 15, 2009 at 3:44 PM, Jervis Whitley <jervi...@gmail.com> > wrote: > > how about this: > > items = [(1,'a'),(1,'b'),(2,'a'),(3,'a'), > > (3,'b'),(4,'a'),(5,'a'),(5,'b'),(5,'c')] > > mydict = dict(items) > > items = [item for item in mydict.iteritems()] > > That only coincidentally preserves order; the order of items in a > dictionary is, for practical purposes, unpredictable. > > BTW [item for item in mydict.iteritems()] can be written as just > mydict.items(). > > Kent I realise that what you have said is true, however can you show me a case where > items = dict(items).items() will not preserve order? Thanks.
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