On Fri, Jan 16, 2009 at 10:39 AM, bob gailer <bgai...@gmail.com> wrote:
> Jervis Whitley wrote: > >> >> >> On Fri, Jan 16, 2009 at 9:15 AM, Kent Johnson <ken...@tds.net <mailto: >> ken...@tds.net>> wrote: >> >> On Thu, Jan 15, 2009 at 3:44 PM, Jervis Whitley >> <jervi...@gmail.com <mailto:jervi...@gmail.com>> wrote: >> > how about this: >> > items = [(1,'a'),(1,'b'),(2,'a'),(3,'a'), >> > (3,'b'),(4,'a'),(5,'a'),(5,'b'),(5,'c')] >> > mydict = dict(items) >> > items = [item for item in mydict.iteritems()] >> >> That only coincidentally preserves order; the order of items in a >> dictionary is, for practical purposes, unpredictable. >> >> BTW [item for item in mydict.iteritems()] can be written as just >> mydict.items(). >> >> Kent >> >> I realise that what you have said is true, however can you show me a case >> where >> > items = dict(items).items() >> >> will not preserve order? Thanks. >> >> > On my computer: > > >>> dict((('z', 1), ('y', 2))).items() > [('y', 2), ('z', 1)] > > -- > Bob Gailer > Chapel Hill NC > 919-636-4239 > Same on mine, thanks.
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