64-bit Vista
Python 3.2.1
I would like to write a function that would take a path such as
'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf'
and return 'C:/Users/Dick/Desktop/Documents/Notes/College Notes.rtf' . I've
tried this:
def test(path):
return path.replace('\', '/')
print(test('C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf'))
gets me
File "c:\P32Working\untitled-5.py", line 2
return path.replace('\', '/')
^
SyntaxError: EOL while scanning string literal
Process terminated with an exit code of 1
Thanks,
Dick
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