Sandip Bhattacharya wrote:
> On Sat, Jul 30, 2011 at 10:28:11PM -0700, Richard D. Moores wrote:
>> File "c:\P32Working\untitled-5.py", line 2
>> return path.replace('\', '/')
>> ^
>> SyntaxError: EOL while scanning string literal
>> Process terminated with an exit code of 1
>
> The first backslash up there is escaping the ending quote. This is what
> you want:
> return path.replace('\\', '/')
>
> Generally, converting slashes manually should be kept at a minimum. You
> should be using library functions as much as possible. The experts here
> can correct me here, but this is a roundabout way I would be doing this:
>
> # I use a linux machine. Using this to work with Windows paths
> # Use os.path if you are on windows
> import ntpath
>
> # Use raw strings so that backslash doesnt matter
> path=r'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf'
>
> #take out drive first because ntpath.split end sentinel is predictable
> #that way
> drive,rest = ntpath.splitdrive(path)
>
> # This will store the path components
> comps = []
> comps.append(drive)
>
> while rest != '\\':
> parts = ntpath.split(rest)
> comps.insert(1,parts[1])
> rest = parts[0]
>
>
> print '/'.join(comps)
>
> I am not happy with the loop to collect the components. But I couldn't
> find a single path function which splits a path into all the components
> in one go.
What happens if the path looks like
r"C:relative\path\to\my\file.txt"
or
r"C:/mixed\slashes.txt"?
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