Ruchard,
Try return path.replace('\\', '/'). That gave me the output desired by you.
I don't know the reason. But I guess it's because \ is used as escape
character. I am sure someone in the list will point out the accurate reason.
On Sun, Jul 31, 2011 at 10:58 AM, Richard D. Moores <[email protected]>wrote:
> 64-bit Vista
> Python 3.2.1
>
> I would like to write a function that would take a path such as
> 'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf'
> and return 'C:/Users/Dick/Desktop/Documents/Notes/College Notes.rtf' . I've
> tried this:
>
> def test(path):
> return path.replace('\', '/')
>
> print(test('C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf'))
>
> gets me
>
> File "c:\P32Working\untitled-5.py", line 2
> return path.replace('\', '/')
> ^
> SyntaxError: EOL while scanning string literal
> Process terminated with an exit code of 1
>
> Thanks,
>
> Dick
>
>
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--
Regards
Dharmit Shah <http://about.me/dharmit>
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