On Tue, Nov 26, 2013 at 10:19:46AM +0100, spir wrote: > What is the method to get a code or list of codes inside a string: > s = "abcde" > c = s.code(2) > assert(c == 0x63) > ?
Use indexing to get the character you want, then ord() to return its ordinal value. ord(s[2]) > === sub compare === > > Is there a method to compare a substring, without building a substring from > the big one? Like startswith or endswith, but anywhere inside the string? > test = s[1, -1] == "bcd" # no!, builds a substring > test = s.sub_is(1, -1, "bcd") # yes! what I'm searching The word I think you want is "view". A view is a look inside another object without copying the part that you want. I think that views would be useful for *very large strings*, but very large probably means a lot larger than you might think. For small strings, say under a few hundred or perhaps even thousand characters, making a copy of the substring will probably be faster. I say "probably", but I'm only guessing, because strings in Python don't have views. (Perhaps they should?) So for the time being, don't worry about it. Copying a substring in Python is very efficient, the simplest way is to just compare the substring directly: s[1:-1] = "bcd" Take note that a slice (substring) of a string uses a colon : and not a comma. -- Steven _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: https://mail.python.org/mailman/listinfo/tutor
