On 26/11/13 11:59, Steven D'Aprano wrote:
test = s.startswith("bcd", 1, -1)
That doesn't work, unfortunately:
py> s = "abcdZZZZZZZ"
py> s[1:-1] == "bcd"
False
py> s.startswith("bcd", 1, -1)
True
Oops.
You'd have to do both startswith() and endswith() tests, and even then
it doesn't work:
Since the OP suggested startswith/endswith I assumed that's what he
wanted... His example:
s = "abcde"
test = s[1, -1] == "bcd" # no!, builds a substring
test = s.sub_is(1, -1, "bcd") # yes! what I'm searching
tests the substring 'bcde' and apparently was expected to
return True for 'bcd'... hence the suggestion to use
startswith
If he wants to test for equality of a substring then
provided the start/end are set correctly startwith will
still work, but you need to ensure that end is exactly
(start+len(subst)). ie
test = s.startswith('bcd', 1, 1+len('bcd') )
And that's a bit error prone so I'd still opt for slicing.
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.flickr.com/photos/alangauldphotos
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