I got cracking on testing this out... no luck (yet). Here's my testing code
if some kind person could please take a look....
First my generic collection hierarchy (which only contains a name and
children)...
package jxpathresearch;
import java.util.ArrayList;
public class HierarchyPojo extends ArrayList<HierarchyPojo> {
public HierarchyPojo(String name){
this.setName(name);
}
private String name = "";
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
Next, the wrapper for the root context (as Matt suggested) and populated
with animals...
package jxpathresearch;
public class CollectionRoot {
private HierarchyPojo hierarchyPojo;
public CollectionRoot(){
//Animal
hierarchyPojo = new HierarchyPojo("Animal");
//Animal.Dog
HierarchyPojo dog = new HierarchyPojo("Dog");
//Animal.Dog.Labrador
dog.add(new HierarchyPojo("Labrador"));
//Animal.Dog.Boxer
dog.add(new HierarchyPojo("Boxer"));
//Animal.Dog.Mastiff
dog.add(new HierarchyPojo("Mastiff"));
//Animal.Cat
HierarchyPojo cat = new HierarchyPojo("Cat");
//Animal.Cat.Tiger
cat.add(new HierarchyPojo("Tiger"));
//Animal.Cat.Cougar
cat.add(new HierarchyPojo("Cougar"));
//Animal.Cat.Leopard
cat.add(new HierarchyPojo("Leopard"));
//Add Animal.Dog & Animal.Cat
hierarchyPojo.add(dog);
hierarchyPojo.add(cat);
}
public HierarchyPojo getHierarchyPojo() {return hierarchyPojo;}
public void setHierarchyPojo(HierarchyPojo hierarchyPojo)
{this.hierarchyPojo = hierarchyPojo;}
}
Finally invoke and test...
public class App
{
public static void main( String[] args )
{
JXPathContext context = JXPathContext.newContext(new
CollectionRoot());
String query = "//hierarchypo...@name='Tiger']";
String fName = context.getValue(query).toString();
System.out.println("Ran '"+query+"' and got '"+fName+"'");
}
}
Above, should find one entry for 'name=Tiger' but it does not, I get an
exception. This still doesn't seem to traverse the Collection correctly. Any
help would be most welcome.
Exception in thread "main"
org.apache.commons.jxpath.JXPathNotFoundException: No value for xpath:
//hierarchypo...@name='Tiger']
Thanks for reading,
Andrew
On Mon, Feb 9, 2009 at 10:24 PM, Andrew Hughes <ahhug...@gmail.com> wrote:
> Thanks Matt - I will test this out tomorrow when I am back in the office...
>
> Being constructive...
> Surely this should at least be a precondition check and throw a specific
> exception if it's not supported?
> Thank You
> --Andrew
>
>
> On Mon, Feb 9, 2009 at 2:27 PM, Matt Benson <gudnabr...@yahoo.com> wrote:
>
>>
>> Most likely your problem is not with generics, but simply with the fact
>> that JXPath has a hard time using a collection as its root. The easiest
>> workaround is to use some parent object to hold a reference to your
>> container.
>>
>> HTH,
>> Matt
>>
>>
>> --- On Sun, 2/8/09, Andrew Hughes <ahhug...@gmail.com> wrote:
>>
>> > From: Andrew Hughes <ahhug...@gmail.com>
>> > Subject: JXPath over Generic Collection<?>, How?
>> > To: "Commons Users List" <user@commons.apache.org>
>> > Date: Sunday, February 8, 2009, 5:09 PM
>> > Hi All,
>> > Hopefully the solution is as easy as the question. I would
>> > like to perform
>> > evaluation on a (very simple) generic collection... as you
>> > can see below
>> > (HeirarchyPojo). I should be able to ask for a
>> > HeirarchyPojo's with
>> > name='Bill' or the 3rd Child... The problem is that
>> > nothing ever evaluate on
>> > this data structure. What's the deal with Generic
>> > Collections and JXPath?
>> >
>> > p.s this is not in the userguide and would be a most
>> > welcomed addition (if
>> > we can nut this out with your help).
>> >
>> > Cheers.
>> >
>> >
>> > package xpath.and.generics;
>> >
>> > import java.util.ArrayList;
>> >
>> > public class HeirarchyPojo extends
>> > ArrayList<HeirarchyPojo>{
>> >
>> > public HeirarchyPojo(){}
>> >
>> > private String id;
>> > private String name;
>> >
>> > public String getId() {
>> > return id;
>> > }
>> >
>> > public void setId(String id) {
>> > this.id = id;
>> > }
>> >
>> > public String getName() {
>> > return name;
>> > }
>> >
>> > public void setName(String name) {
>> > this.name = name;
>> > }
>> >
>> > }
>>
>>
>>
>>
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>>
>
