Just making sure you have seen Kapil Anand's post earlier today (Wed). I think that's what you are looking for also. Radu
_____ From: Hildegunde Weinzierl [mailto:[email protected]] Sent: Tuesday, June 16, 2009 4:07 AM To: [email protected] Subject: Antwort: Re: How creating an XmlObject only knowing the name of the generated document class? Hi, yes, but I need the SchemaType of the corresponding MyReportDocument. Best regards Hildegunde Weinzierl
