RE: How creating an XmlObject only knowing the name of the generated document class?

[Gillen, Paul]

Sorry for the late reply; been on vacation.  This may have been answered but 
this is what worked for me (if I understood your question correctly):


    public String validateXml(String aClassName, String aXml)
    {
        outputXml   = null;
        try
        {
            Class           xClass              = Class.forName(aClassName);
            ArrayList       validationErrors    = new ArrayList();
            XmlOptions      typeOptions         = new XmlOptions();
            XmlOptions      validationOptions   = new XmlOptions();
            XmlObject       xmlDocument;
            SchemaType      schemaType          = XmlBeans.typeForClass(xClass);

            validationOptions.setErrorListener(validationErrors);
            typeOptions.setDocumentType(schemaType);

            xmlDocument     = XmlObject.Factory.parse(aXml, typeOptions);

            if (!xmlDocument.validate(validationOptions))
            {
                String      exMsg       = "Validation failed";
                Iterator    iter        = validationErrors.iterator();
                while (iter.hasNext())
                {
                    XmlValidationError valErr = (XmlValidationError)iter.next();
                    exMsg   +=  "\n\t" + valErr.getMessage();
                }
                return exMsg;
            }
            outputXml   = xmlDocument.toString();
            return "XML document is valid";
        }
        catch (Exception e)
        {
            if (e instanceof java.lang.ClassNotFoundException)
            {
                return "Validation failed\n\tSupport library not installed for 
this XML document type";
            }
            return "Validation failed\n\tDocument could not be validated 
(typically invalid XML)";
        }
    }