David, if you have a single pattern, either 10.10.131. or 10.10.131/24
will match the entire subnet. If you have divided it into two different
patterns, I already answered your question.
Please, do some background reading on IPv4 and subnet patterns, that
would tell you that the 10.10.131.128/25 matches 25 bits, 10.10.131.,
and within that, anything with bit 128 (2^7) set. So this pattern
matches 10.10.131.128-.255 inclusive.
Lucas, David wrote:
Does anyone have any thoughts as to how I will get this to match??
Thanks,
Dave
-----Original Message-----
From: Lucas, David
Sent: Monday, August 22, 2005 2:28 PM
To: users@httpd.apache.org
Subject: RE: [EMAIL PROTECTED] mod_rewrite
/25 would be correct.
If you look at Noah response his solution works on the upper half of the
subnet so 10.10.131.128/25 is matched. I need the lower half now.
Dave
-----Original Message-----
From: William A. Rowe, Jr. [mailto:[EMAIL PROTECTED]
Sent: Monday, August 22, 2005 2:09 PM
To: users@httpd.apache.org
Subject: Re: [EMAIL PROTECTED] mod_rewrite
Lucas, David wrote:
Ok,
How might I match?
10.10.131.0 - 10.10.131.127
10.10.131.0/25
is the standard syntax for oddball subnetting.
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