On Wed, Jan 5, 2011 at 4:32 PM, Phillip Hellewell <ssh...@gmail.com> wrote: > > My question now is, if I want to define the <resources> in a separate > stand-alone xml file (actually there will be more than one), rather > than in the pom.xml, what code/class do I use to read an xml file into > a java.util.List of org.apache.maven.model.Resource?
Would it work to take read the <resources> tag from my XML, surround it with <project><build> </build></project> or whatever to make it a valid pom, and then use the MavenXpp3Reader to parse that? I think I found the code where it parses a Resource, and obviously I don't want to duplicate that code in my own plugin: http://maven.apache.org/ref/2.0.11/xref/org/apache/maven/model/io/xpp3/MavenXpp3Reader.html#4474 Phillip --------------------------------------------------------------------- To unsubscribe, e-mail: users-unsubscr...@maven.apache.org For additional commands, e-mail: users-h...@maven.apache.org
