Hi
This is the first line in my java servlet ukjava1900 it compiles OK
package formprocessors;
is it complete?
I attach copy of my web.xml which i think is OK?
Kind regards
John
On 1 July 2010 14:08, Pid <[email protected]> wrote:
> On 01/07/2010 13:26, Shay Rojansky wrote:
>> /servlet/com/multitel/ukjava1900). Change this to
>
> "/servlet/ukjava1900"
>
> according to the HTML form 'action' attribute.
>
> Also, a minor pedantic note: conventionally, classes are defined with
> capitalised names. So one would expect to see it called
> "com.multitel.UkJava1900.class"
>
>
> p
>
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<?xml version="1.0" encoding="ISO-8859-1"?>
<!--
Licensed to the Apache Software Foundation (ASF) under one or more
contributor license agreements. See the NOTICE file distributed with
this work for additional information regarding copyright ownership.
The ASF licenses this file to You under the Apache License, Version 2.0
(the "License"); you may not use this file except in compliance with
the License. You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS" BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
-->
<web-app xmlns="http://java.sun.com/xml/ns/javaee";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd";
version="2.5">
<display-name>Welcome to Mult-i-tel International</display-name>
<description>
Welcome to Mult-i-tel International
</description>
<servlet>
<servlet-name>ukjava1900</servlet-name>
<servlet-class>webapps/comlinks/WEB-INF/classes/formprocessors/ukjava1900</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>ukjava1900</servlet-name>
<url-pattern>/ukjava1900</url-pattern>
</servlet-mapping>
</web-app>
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