On Tuesday, August 19, 2003, at 03:30 PM, John Niven wrote:
Now this got me thinking - why can I only use 8MB of program RAM? It's called 24 bit addressing, but 2 to the power of 24 is a 16M address space.
I also have a Classic II that has 10MB of RAM (2MB on the motherboard, and two 4MB simms). When I set this up with OS 6.0.8L I get to play with all 10MB, unless I'm mistaken (it was a while ago).
So what holds OS 6 back to 8MB, and why isn't that referred to as 23bit addressing? If there is no other way around it I may go back to 8MB of RAM so the machine boots faster.
Confused, John
I've just confirmed that my Classic II, running OS 6.0.8L, has a total memory of 10,240KB, the largest free block is 9,102KB, Finder uses 160KB, while the system uses 978KB. Does this elevate the Classic II from "Road Apple" status as a OS 6 machine? :-)
So if I could get OS 6.0.8L to run on my IIci, could I get it to recognize more than 8MB?
Any ideas?
John
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