First it must be determined that nickel based systems can not generate 
electricity in the same general manner.   So far we have not actually seen 
proof that either metal works all that well.   I remain skeptical until more 
evidence becomes available in support of this concept.

I wonder what fraction of the energy release can be directly converted into 
electricity?   Unless it is a large proportion some form of heat powered 
generator is going to be required anyway.  The overall system will have to be 
optimized.

Dave

 

 

 

-----Original Message-----
From: Axil Axil <janap...@gmail.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Thu, Nov 19, 2015 11:28 pm
Subject: Re: [Vo]: How many atoms to make condensed matter?



The cost is cheap if the reactor can produce electricity directly.


On Thu, Nov 19, 2015 at 11:21 PM, David Roberson <dlrober...@aol.com> wrote:

The counts for elements of that m value appear quite small when compared to the 
other elements.  Also, why on earth would anyone use such an expensive element 
if a dirt cheap one can substitute?  My suspicion is that this is a dead end 
idea if production costs are taken into consideration.

Dave

 

 

 

-----Original Message-----
From: Eric Walker <eric.wal...@gmail.com>
To: vortex-l <vortex-l@eskimo.com>
Sent: Thu, Nov 19, 2015 10:27 pm
Subject: Re: [Vo]: How many atoms to make condensed matter?





On Thu, Nov 19, 2015 at 7:34 PM, David Roberson <dlrober...@aol.com> wrote:


Rossi has never mentioned palladium use within his reactors Axil.  That is your 
thought as far as I am aware.




I don't know whether Rossi is now using or has used palladium in the past. But 
one detail in the Lugano report that only became apparent to me much later was 
that there appears to have been a number of heavy elements in one of the fuel 
assays in Appendix 3 (see the lower graph, outlined in red).


http://i.imgur.com/7RQon11.png



Some of these heavier masses were likely to have been compound ions. But it's 
seems unlikely that 100 percent of them were.  Note that palladium overlaps 
with m=105.  Even if palladium were not present, I would not be surprised if 
one or more heavier elements were.


I do not know why this was the only instance in which a graph for m>100 was 
shown in the appendix.


Eric











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