I suppose an appropriate comparison would be with resistive heating from electricity.
Crude oil can serve as a primary source of energy because more energy can be gained from burning it then is required to extract it. (I think in oil's heyday 1 barrel of oil was required to get 10 barrels of oil) Harry On Sat, Jan 19, 2019 at 3:05 PM David L. Babcock <olb...@gmail.com> wrote: > I hope that was snark... Not much could beat a match. > > On Sat, Jan 19, 2019 at 1:35 PM H LV <hveeder...@gmail.com> wrote: > >> If the goal is the conversion of energy into heat rather than the >> production of energy (0U), how efficient is this method compared to other >> methods? I mean if LENR or CF proves to be impractical as a primary source >> of energy then perhaps it's true value is in the production of heat. Harry >> >> On Sat, Jan 19, 2019, 1:03 AM bobcook39...@hotmail.com < >> bobcook39...@hotmail.com wrote: >> >>> Jones— >>> >>> >>> >>> I agree with you. I did not catch the meaning of the “wall” in your >>> discussion with Jack. I agree that it should be easy to measure >>> electrical AC energy consumed by the pulse generator. >>> >>> >>> >>> I was focusing on the question of energy into the reactor introduced by >>> the pulse for comparison with energy out, over and above that coming >>> out. >>> >>> >>> >>> I also find it hard to believe that the folks funding the testing did >>> not understand the losses of energy in the pulse generator, which were not >>> contributing to stimulation of the reactor to release potential energy >>> whatever that source might be. >>> >>> >>> >>> Bob Cook >>> >>> >>> >>> >>> >>> >>> ------------------------------ >>> *From:* Jones Beene <jone...@pacbell.net> >>> *Sent:* Friday, January 18, 2019 3:48:58 PM >>> *To:* vortex-l@eskimo.com >>> *Subject:* Re: [Vo]:Robert Godes podcast >>> >>> bobcook wrote: >>> >>> > You say it is easy to measure pulsed power at the wall of the Godes >>> reactor and suggest the measurements were accomplished, but covered up... >>> You should suggest a method to do this “easy” measurement. >>> >>> Bob, >>> >>> Apparently my main underlying assumption - which is apparently reversed >>> from yours - is that the energy expended to create the special pulses MUST >>> BE included as part of the input - even if it is much higher than what is >>> actually contained in the pulses when they appear at the reactor. There is >>> no free lunch obtainable from comparing low grade power (heat) to extremely >>> high grade power (pulsed charges). >>> >>> For instance if pulse creation expends 50% more energy than grid AC - >>> but is absolutely required for success, then one cannot logically ignore >>> the loss and claim OU when much or all of the gain is required to make the >>> pulses initially. IOW - one cannot assert that the net energy of producing >>> a complex waveform should not also include all of the losses. >>> >>> High grade power is special - very special, and the losses have to >>> included to calculate net gain. >>> >>> Thereforw to answer your question specifically, anyone can buy a simple >>> AC wattmeter from Amazon for 20 bucks to do the job of ascertaining real >>> input power from the grid. It is beyond belief to suggest that this was not >>> done. >>> >>> >>>
