On Dec 15, 2008, at 12:36 PM, mix...@bigpond.com wrote:
Considerable energy release doesn't necessarily result in
radioactivity. As you
so astutely point out Fe56 + 2P = Ni58, which is stable.
Under conventional theories, making Ni58 from Fe56 requires
substantial energy to supply the extra mass. This is on the downward
sloping side of the curve of binding energy. Consider:
Mass of particles
(in AMU)
55.934939 Fe56
1.007825 p
1.007825 p
-57.935346 Ni58
==========
0.015243
The energy deficit is therefore (0.015243 AMU)* (931.5 MeV/(AMU/c^2)
= 1.4198 MeV/c^3. However, this is no problem for a deflated
hydrogen reaction, as a energy deficit naturally occurs anyway in the
wave function collapse, and the zero point field makes up the
difference in expanding the deflated electron. The problem is setting
up conditions for this to occur. An explosion is not the right
condition because the deflated state exists for too short an interval
to have any effect in ordinary high energy collisions. However,
given billions of years, adsorbed hydrogen should be able to work
this kind of transmutation until essentially no hydrogen is available.
It is notable that Cosmic rays are a significant source of protons,
so the hydrogen can never be totally exhausted, and the cosmic rays
carry much more than the 1.5 MeV (or 2 * 0.75 MeV) needed to pull
off this kind of reaction directly. A bigger problem might be
explaining why the transmutation process essentially stops with Ni58.
Best regards,
Horace Heffner
http://www.mtaonline.net/~hheffner/
