on Mon, 28 Dec 2009 13:17:23 -0800 Stephen A. Lawrence very correctly said
[snip] But why do you think there would be less energy needed to unload the Pd than it released during loading? Nothing in these results suggests that. Certainly if picogravity is at the bottom of it, you're dealing with a conservative force, and what comes out must go back in if you're return to your starting conditions. Casimir is going to behave conservatively too in situations where all you're doing is letting things smash together and then yanking them apart again. [end snip] Yes! The force is conservative unless you perform a chemical reaction while the atoms are in the depleted zone. Without taking sides about whether the orbitals are fractional , pancaked, relativistic or whatever I think we will all agree they are in some way different than atoms outside of a Casimir cavity. If these orbitals form into a compound or molecule their orbitals become locked into a specific mode or orientation that is NOT appropriate for the isotropic field outside the cavity. As the bonded atoms diffuse away from the specific depletion level where they bonded the gradient of the depletion field changes in opposition to the molecular bond - I suspect that the bond is broken by this opposition and that a hydrino will never be seen outside of the cavity but it may be strong enough to maintain a weak hydrino or FH outside the cavity. See animation http://www.byzipp.com/finished1.swf the atoms once decelerated by the cavity can oscillate between monatomic and diatomic until they escape the depletion field - the normally chaotic vacuum fluctuations are able to donate energy in a non chaotic manner thanks to the energy sink of the cavity. The favored molecular bond becomes our rectifier when formed by "altered" atoms that find themselves no longer able to "unaltered" because the bond is holding them in the altered state despite the restoration of the ZPF when the molecule diffuse away from the particular gradient of depletion (1/(2-137) at which it formed.
