At 10:02 PM 6/20/2011, Stephen A. Lawrence wrote:
Rossi's explanation is not sound, that the steam isn't so visible
because it's so hot. It's at normal temperature for steam!!!
Measured at between 100 and 102C, in fact, according to what I've read.
So, no, it's not superheated steam.
Right. The explanation was BS.
It will cool and condense, becoming visible, when it hits the
ambient air. The only difference that will exist for various flow
rates will be an increase in the plume size and an increase in the
apparent velocity of any turbulence in it. The margin between the
opening of the hose and the point at which the steam becomes
visible will become larger (because it probably takes about the
same time to cool, but if it's moving faster, it will travel
further in that time.)
The instability of the viewing of the steam plume is disappointing.
I just looked again. I think I can see steam all the way down to
the hose, which would imply that this is not dry steam, not
completely, not exiting the hose. It might have been dry coming out
of the E-Cat. The place to observe the steam would be at the valve,
which they have completely covered here. The temperature inside the
hose at the end would be of interest. If it's cooler, that would
explain the visibility of steam.
It's going to be within a degree or so of 100C, which is the
reported temperature in the chimney. Certainly no cooler, since
there's steam coming out, and certainly not much warmer. So, I
don't think you'd see anything interesting with two thermometers.
I don't know that there is steam coming out. What's coming out is a
cloud, i.e., condensed steam, though it looks like a mixure (because
it does seem to become more visible above the hose), so I think some
steam is making it to the end of the pipe. Still, there might be a
fraction of a degree of temperature difference. It's really moot. The
steam should be examined at the other end, at the top of the chimney,
with a valve, as was done by Essen and Kullen.
Remember, steam with entrained droplets is "buffered", and will stay
at almost exactly 100C even if it either gives up or absorbs some
amount of heat. (This is the "internal feedback" mechanism I've
referred to elsewhere.)
Yes, it is.
