I sited this link in my poat, you must have missed it. http://everything2.com/title/proton-proton+chain
See the PPIII section at the end of list. Cheers: Axil On Mon, Aug 20, 2012 at 12:37 AM, Abd ul-Rahman Lomax <a...@lomaxdesign.com>wrote: > I think the Be-8 ground state decay to 2 He-4 is at about the 93 KeV > figure. Not the higher figure. Where did you get 18 MeV? > > > > > My understanding is that 4D -> Be-8 + about 47.6 MeV, which is initially > as a nuclear excited state. Some of that may be emitted as a series of > photons. If the Be-8 nucleus lasts long enough, it will decay to the ground > state, leaving only the 93 KeV to show up as dual He-4 kinetic energy. If > the initial fusion was within a BEC, there may also be 4 electrons to share > the energy. It's a stretch, but this is a rough idea of how TSC fusion > might meet the Hagelstein limit for charged particle radiation in the FPHE. > I'm not saying I believe it! > > Sent from my iPhone > > On Aug 19, 2012, at 4:08 PM, Axil Axil <janap...@gmail.com> wrote: > > What I don’t understand is if this is possible: > > 1 - 4He + 4He → 8Be(-93.7kEV) > 2 - Be8 -> 2He4(18.074 MeV) > > If this reaction is possible, and if this is what recombination is, where > does the 18 MeV come from. > Axil > > On Sun, Aug 19, 2012 at 3:31 PM, Axil Axil <janap...@gmail.com> wrote: > >> When the electrons fall back into their ground states we can comfortably >> assert that the photons emitted will equal the energy input. >> >> This is a bad assumption. >> >> If two helium atoms fuse about 18 MeV is produced along with a positron >> and a neutrino. I do not understand this reaction. Maybe someone can help. >> >> http://everything2.com/title/proton-proton+chain >> >> In the PPIII stellar fusion reaction, Steps 1 through 3 can be replaced >> by the first half of the triple alpha stellar fusion process >> >> http://en.wikipedia.org/wiki/Triple-alpha_process >> >> Explicitly >> >> 1 - 4He + 4He → 8Be(-93.7kEV) >> >> 2 – 8Be + proton → B8 (0.135 MeV) - other possible reactions involver >> electron and hydrogen capture. >> >> 3 - B8 -> Be8 + positron + neutrino (followed by spontaneous decay...) >> >> 4 - Be8 -> 2He4(18.074 MeV) >> >> We start out with two helium atoms and we end up with two helium atoms >> but about 19MeV of additional energy is produced. >> >> Where does this energy come from? >> >> J. Rohner says that he stops the triple alpha stellar fusion process >> before a third helium atom is fused. He calls this process recombination as >> the Be8 fissions back to two helium atoms. >> >> >> Cheers: Axil >> >> >> On Sun, Aug 19, 2012 at 1:44 PM, James Bowery <jabow...@gmail.com> wrote: >> >>> Let's say you've got a xenon atom. It likes to absorb energy and emit >>> photons. You know, xenon lamps etc. >>> >>> OK, so lets ask a real simple question: >>> >>> When a tube filled with xenon gas has some energy pumped into it and the >>> electrons go to higher orbitals -- yes this happens for a very short period >>> of time before photons are emitted but let's talk about just the short >>> period of time. The diameter of the atoms presumably increases. Does the >>> gas pressure increase during that interval? >>> >>> Now lets say that the energy is sufficient to actually strip the >>> electrons away and form an ionized gas for a short interval. Does the >>> ionized gas pressure increase during that interval? >>> >>> Now lets talk about really-simple magnetic confinement (say a magnetic >>> mirror <http://en.wikipedia.org/wiki/Magnetic_mirror> type bottle) used >>> in conjunction with a solid tube so that the non-conducting (because >>> non-ionized) gas phase is confined by the solid tube and the conducting >>> (because) ionized gas phase is confined by the magnetic bottle: >>> >>> When the electrons fall back into their ground states we can comfortably >>> assert that the photons emitted will equal the energy input. However, what >>> if the plasma has expanded during the high pressure phase, ie: done work >>> against the magnetic confinement (like, oh, I don't know, generating an >>> electrical power spike in a conductor associated with the magnetic field). >>> Does that mean the "free" electrons of the plasma no longer want to return >>> to their ground states and give up exactly the same amount of energy that >>> they would have in the absence of having done work? If not, where did the >>> electrons go and where do the xenon atoms get electrons to substitute for >>> them? >>> >> >> >