I think that must be an excited state decay. But I don't know. For a
ground state decay, that's very high. What's the mass defect?
Sent from my iPhone
On Aug 20, 2012, at 12:55 AM, Axil Axil <janap...@gmail.com> wrote:
I sited this link in my poat, you must have missed it.
http://everything2.com/title/proton-proton+chain
See the PPIII section at the end of list.
Cheers: Axil
On Mon, Aug 20, 2012 at 12:37 AM, Abd ul-Rahman Lomax <a...@lomaxdesign.com
> wrote:
I think the Be-8 ground state decay to 2 He-4 is at about the 93 KeV
figure. Not the higher figure. Where did you get 18 MeV?
My understanding is that 4D -> Be-8 + about 47.6 MeV, which is
initially as a nuclear excited state. Some of that may be emitted as
a series of photons. If the Be-8 nucleus lasts long enough, it will
decay to the ground state, leaving only the 93 KeV to show up as
dual He-4 kinetic energy. If the initial fusion was within a BEC,
there may also be 4 electrons to share the energy. It's a stretch,
but this is a rough idea of how TSC fusion might meet the Hagelstein
limit for charged particle radiation in the FPHE. I'm not saying I
believe it!
Sent from my iPhone
On Aug 19, 2012, at 4:08 PM, Axil Axil <janap...@gmail.com> wrote:
What I don’t understand is if this is possible:
1 - 4He + 4He → 8Be(-93.7kEV)
2 - Be8 -> 2He4(18.074 MeV)
If this reaction is possible, and if this is what recombination is,
where does the 18 MeV come from.
Axil
On Sun, Aug 19, 2012 at 3:31 PM, Axil Axil <janap...@gmail.com>
wrote:
When the electrons fall back into their ground states we can
comfortably assert that the photons emitted will equal the energy
input.
This is a bad assumption.
If two helium atoms fuse about 18 MeV is produced along with a
positron and a neutrino. I do not understand this reaction. Maybe
someone can help.
http://everything2.com/title/proton-proton+chain
In the PPIII stellar fusion reaction, Steps 1 through 3 can be
replaced by the first half of the triple alpha stellar fusion process
http://en.wikipedia.org/wiki/Triple-alpha_process
Explicitly
1 - 4He + 4He → 8Be(-93.7kEV)
2 – 8Be + proton → B8 (0.135 MeV) - other possible reactions
involver electron and hydrogen capture.
3 - B8 -> Be8 + positron + neutrino (followed by spontaneous
decay...)
4 - Be8 -> 2He4(18.074 MeV)
We start out with two helium atoms and we end up with two helium
atoms but about 19MeV of additional energy is produced.
Where does this energy come from?
J. Rohner says that he stops the triple alpha stellar fusion
process before a third helium atom is fused. He calls this process
recombination as the Be8 fissions back to two helium atoms.
Cheers: Axil
On Sun, Aug 19, 2012 at 1:44 PM, James Bowery <jabow...@gmail.com>
wrote:
Let's say you've got a xenon atom. It likes to absorb energy and
emit photons. You know, xenon lamps etc.
OK, so lets ask a real simple question:
When a tube filled with xenon gas has some energy pumped into it
and the electrons go to higher orbitals -- yes this happens for a
very short period of time before photons are emitted but let's talk
about just the short period of time. The diameter of the atoms
presumably increases. Does the gas pressure increase during that
interval?
Now lets say that the energy is sufficient to actually strip the
electrons away and form an ionized gas for a short interval. Does
the ionized gas pressure increase during that interval?
Now lets talk about really-simple magnetic confinement (say a
magnetic mirror type bottle) used in conjunction with a solid tube
so that the non-conducting (because non-ionized) gas phase is
confined by the solid tube and the conducting (because) ionized gas
phase is confined by the magnetic bottle:
When the electrons fall back into their ground states we can
comfortably assert that the photons emitted will equal the energy
input. However, what if the plasma has expanded during the high
pressure phase, ie: done work against the magnetic confinement
(like, oh, I don't know, generating an electrical power spike in a
conductor associated with the magnetic field). Does that mean the
"free" electrons of the plasma no longer want to return to their
ground states and give up exactly the same amount of energy that
they would have in the absence of having done work? If not, where
did the electrons go and where do the xenon atoms get electrons to
substitute for them?
