Jim, why assume the neutron is stripped from the D? This requires 1.7
MeV/event. Where does this amount of energy come from? We know that
fractofusion occurs when D is present and this produces neutrons. An
explosive reaction would certainly create cracks in the container that
could cause this version of hot fusion.
Ed
On Mar 14, 2013, at 3:21 PM, James Bowery wrote:
On Thu, Mar 14, 2013 at 10:49 AM, Jones Beene <jone...@pacbell.net>
wrote:
The chlorine-hydrogen photoactivated reaction is the only chemical
reaction which is known to produce nuclear reactions (when deuterium
is used in place of hydrogen). Neutrons are “stripped” from the
deuterium in that case.
Normal water is 0.02% D2O, so can't we expect:
2014101.77812 + 15994914.61957 => 16999131.75650 + 1007825.03223 +
2059.609uamu energy
D + O16 => O17 + H + 2059.609uamu energy
in appropriately dilute amounts?
