Jones,
Are you saying that there are two reactions taking place in this situation where the final product results in the release of energy? I agree with Ed if the end products are a neutron and proton that are now unconnected. Perhaps it is possible to borrow energy for a short period of time with a quantum tunneling effect, but it must be repaid soon afterwards. Please explain when that happens. Dave -----Original Message----- From: Jones Beene <jone...@pacbell.net> To: vortex-l <vortex-l@eskimo.com> Sent: Thu, Mar 14, 2013 9:06 pm Subject: RE: [Vo]:Dilute D2O Cold Neutron Capture In Papp Engine? From:Edmund Storms Here is themass change D = 2.014101778 H= 1.00727647 n= 1.0086649 The gain inmass is D-n= p You are making an incorrect assumption. The O-P effect (i.e.“stripping”) is not thermonuclear, it is quantum mechanical - ineffect a tunneling reaction. Quantum tunneling is one of Oppenheimer’sclaims to fame. OK Jones, then were does the mass come from? Nomatter what you call the process, the energy MUST be conserved. Thisreaction requires energy be added to create the mass of the product. Where doesthis energy come from? Yes, mass-energy isconserved but we are talking about deuterium being converted into somethingelse (tritium or He3)– so there is NOT necessarily a non-conserved massof anything, since there is always the neutrino “wild card”. That, essentially,is the crux of your incorrect assumption. In the Fusor, the transmuted nucleus is left in an energy state asif it had fused with a neutron of negative kinetic energy, so there far lessmass change than the thermonuclear reaction. The Fusor can be called“warm fusion” not hot, since the threshold energy for thermonuclearreaction is never attained. The only issue here is how the barrier is overcome,because once this happens, energy is created by the normal hot fusion reaction,i.e. the combined nucleus fragments into the observed particles which includesneutrons. That is what you seem tobe missing in all of this. It is not hot fusion but CoE does apply. In the O-Preaction, the Coulomb barrier is overcome when two deuterons approach eachother with the neutron end of each facing the other – i.e. being geometricallyahead of the proton end. The 1.7 MeV barrier is effectively lowered to about 10keV. Why suggest some magic condition like negative energy. Robert Oppenheimer andMelba Philips suggested this. Who am I, or you, to suggest otherwise? The process is very simple. The two D are given enoughenergy to surmount the barrier. The Fusor simply does this in an efficient way. No, the Fusor never getsclose to doing this at all, without QM. The energy to surmount the barrier isreduced by a similar amount to the deficit in net energy transfer. Once again, we appear tobe seeing experts in one field who do not understand the full implications ofQM and nuclear tunneling - and refuse to believe that energy on the quantumscale can be “borrowed” for a few femtoseconds before it is repaid. There is no 1.7 MeVthreshold and there is corresponding mass change. In QM tunneling, the energybarrier for fusion is reduced and the excess energy is likewise reduced. Jones
