Jones, I assume you accept that E=mc2 and that if the mass of a
reaction changes, the energy has to come from somewhere.
Here is the mass change
D =
2.014101778
H=
1.00727647
n=
1.0086649
The gain in mass is D-n= p
-0.001839592
which =
1.713569649
MeV has to be added to provide the increased mass of the resulting p.
The Farnsworth Fusor is producing hot fusion, which generates energy.
The only issue is what amount of energy must be applied to overcome
the Coulomb barrier, after which energy is released. That amount to
get over the barrier can be a few kev to cause a little hot fusion.
In the case of neutron stripping, energy must be ADDED to the system
to produce the result.
On the other hand, if you assume that the chemical reaction is
creating hot fusion in the gas, then you must assume that each D has
been given a 10 keV as kinetic energy as a result of the chemical
reaction. That is not possible because to make any energy the DCl
molecule has to form, which can not have the required kinetic energy
simply based on momentum considerations.
Ed
On Mar 14, 2013, at 4:09 PM, Jones Beene wrote:
From: Edmund Storms
Jim, why assume the neutron is stripped from the D? This requires
1.7 MeV/event.
No it doesn’t - that number is way off - 3 orders of magnitude off.
Neutron stripping occurs as low as 10 keV. See Tom Ligon’s IE article.
The Farnsworth Fusor is documented proof of large neutron production
at keV energy levels.
Here is another version of Ligon’s article. One can argue the point
of whether this is due to Boltzmann’s tail of the energy
distribution or Oppenheimer-Philips stripping, but one must accept
that it is far removed from 1.7 MeV/event.
http://www.fusor.net/newbie/files/Ligon-QED-IE.pdf
Jones
