A hidden wire at 10 KV would need to carry only 50 mA. That's "small".
A battery would need to supply (say, conservatively) 500 W for 116 hours, or
200 MJ. Lithium batteries are about 2 MJ/Kg, so that's 100 Kg of battery. I
agree that's unlikely but don;t have enough information to make the call.
Andrew
----- Original Message -----
From: Jed Rothwell
To: vortex-l@eskimo.com
Sent: Tuesday, May 21, 2013 1:53 PM
Subject: Re: [Vo]:Levi Hot Cat paper is a gem
Andrew <andrew...@att.net> wrote:
You're missing my point. A power meter looking at wall power is blind to
any internal power source in the box that directly supplies the device with
additional power.
What sort of internal power source?
A generator? That would noisy and obvious.
A battery? That would run out before 5 days elapse. Or, if Rossi has
developed such a battery, it is an important discovery in its own right.
A hidden wire? It would have to be a fairly large wire, to carry 500 to 800
W. They would see it.
Do you have anything else in mind?
- Jed
