Is it the momentum that is shared with a spectator nucleus or the excess energy that wants to cause the He4 to break up? We have been seeking a process that is able to extract the relatively large energy of the excited helium nucleus in a slower than normal manner. I suppose that I refer to normal as being what is seen in high energy physics as compared to LENR.
It seems likely that nearby Coulomb coupled nuclei or other particles would be able to suck up some of the spare energy thereby preventing the destruction of the He4. Perhaps that is what happens when a high energy collision results in the low probability path instead of the usual paths. I can imagine that occasionally three bodies or more might become closely coupled just as the two main D's begin to fuse. Some of the fusion energy might find its way into the spectators. At that point, less than enough energy remains to break up the He4. Dave -----Original Message----- From: mixent <mix...@bigpond.com> To: vortex-l <vortex-l@eskimo.com> Sent: Sat, Jun 22, 2013 7:33 pm Subject: Re: [Vo]:Rossi and DGT Similarity? In reply to Eric Walker's message of Sat, 22 Jun 2013 12:45:33 -0700: Hi, [snip] >> Also, why does the system choose to release energy this way? What rule >> makes this the easiest way? >> > >I'm not sure. This is one of the many questions I have. I have been >trying to understand the system sufficiently to gain insight into these >questions, but it's been a slow learning process. > I suspect, because 4He is very stable, making it the preferred result, whenever this is possible, all else being equal. In D-D hot fusion you get either T or 3He as the primary result, only because these reactions are much faster than gamma emission. However when the momentum can be shared with a spectator nucleus, there is no need for the 4He* to break up, and the reaction to 4He is just as fast (if not faster) than the reaction to T or 3He, hence it is the preferred path. Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
