I have not heard of any reports of tritium being generated by the NiH
reactor. Is tritium a dot that we need to concern ourselves about?


On Thu, Feb 13, 2014 at 7:23 PM, Edmund Storms <stor...@ix.netcom.com>wrote:

> Alain, Math is useless because it is based on conventional mechanisms. The
> process CAN NOT occur in a lattice without violating the laws of
> thermodynamics. The p+e+p is the only form that can also explain tritium
> production. These requirements limit what is possible. Please take them
> into account.
>
> Ed Storms.
>
> Sent from my iPad
>
> On Feb 13, 2014, at 5:03 PM, Alain Sepeda <alain.sep...@gmail.com> wrote:
>
> Seing the idea of  p+e+p plus the fact it can only happen in lattice, in
> some very specific situations, I naturally think about geometry, symmetry...
>
> the error of free space nuclear physicist was to think in free space.
>
> It seems Takahashi have similar ideas, but with different details...
>
> and symmetry can forbid some events, why not p+p? now have to check the
> math...
>
>
>
>
> 2014-02-13 23:57 GMT+01:00 Edmund Storms <stor...@ix.netcom.com>:
>
>> Jones, you keep saying no theory explains LENR and keep suggesting
>> reasons to reject while suggesting your own explanation that is isolated to
>> one part of the process. On the other hand, I suggest a comprehensive
>> mechanism that not only can explain all observations wthout adhoc
>> assumptions but can predict many new behaviors and where to look for the
>> NAE. Is a model that can do this not worth considering seriously rather
>> than reject based on incomplete understanding and arbitrary reasons?
>>
>> Ed Storms
>>
>> Sent from my iPad
>>
>> On Feb 13, 2014, at 3:02 PM, "Jones Beene" <jone...@pacbell.net> wrote:
>>
>>  *From:* H Veeder
>>
>> *(this also answers Robin's more recent posting)*
>>
>>
>> >> The most elegant answer begins with the obvious assertion that there
>> are no
>> gammas ab initio, which means that no reaction of the kind which your
>> theory
>> proposes can be valid because gammas are expected.
>>
>> > RvS: Actually not only would I not expect to detect any gammas from a
>> p-e-p
>> reaction, I wouldn't expect to detect any energy at all. That's because
>> the
>> energy of the p-e-p reaction is normally carried away by the neutrino,
>> which
>> is almost undetectable.
>>
>> JB: the p+p reaction produces a positron, which annihilates with an electron
>> producing 2 gammas. The net energy is over 1 MeV and easily detectable.
>>
>>
>>
>> Electron capture is real, but seldom by a proton at low energy. There is
>> a real reaction in physics, but the ratio of that to p+p is 400:1 ... so we
>> have the insurmountable problem of exclusivity (see below).
>>
>>
>>
>> HV: The process of p-e-p fusion is suppose to be different from the
>> process of p-p fusion. The outcome may be the same, but the processes
>> differ.
>>
>>
>>
>> JB: Again, this is a very rare reaction - and my contention about it is
>> twofold
>>
>>
>>
>> 1)      there is no robust reaction in the real world where protons go
>> directly to a deuteron without first forming a neutron, and that first step
>> is energetically impossible, so the rarity of this p-e-p reaction is
>> ingrained and systemic.
>>
>>
>>
>> 2)      Therefore ... even if there were such a reaction in LENR, at ten
>> or even 100 times greater probability than the known p+p version, consider
>> the obvious problem of exclusivity.
>>
>>
>>
>> Either way it does NOT happen in practice since we know there are no
>> gammas !
>>
>>
>>
>> Consider exclusivity. For the sake of argument - even if there are found
>> to be two possible proton reactions, and one reaction is "supposed to be
>> different" from the known solar reaction, but the outcome is the same
>> except for the gamma - the problem always comes back to one of perfect
>> exclusivity. Exclusivity is the logical fallacy that cannot be overcome.
>>
>>
>>
>> When a gamma reaction is known to happen with the same reactant, how can
>> that reaction be excluded from happening, in a new scenario when both
>> reactions are given enough energy to overcome the fusion threshold?
>> Especially if one (the desired reaction) is much rarer than the other.
>>
>>
>>
>> Simplest answer: the known reaction cannot be excluded from happening,
>> when the energy threshold is met - and there will be gammas even if the
>> hypothetical p-e-p reaction has none by itself.
>>
>>
>>
>> ERGO. We really have no realistic option in framing a proper LENR theory
>> - other than to find a gainful reaction which NEVER produces gammas nor
>> indicia which are not in evidence (bremsstrahlung ).  UV or soft x-rays are
>> ok but no gammas
>>
>>
>>
>> Jones
>>
>>
>>
>> BTW - take an electron and proton at rest, that system has a mass of
>> 0.511 + 938.272 = 938.8 MeV/c^2. That is the total mass available to that
>> system. It cannot increase above that level unless substantial energy comes
>> from outside the system.  A neutron has a mass of 939.6 MeV/c^2.
>>
>>
>>
>> So, to make a neutron from an electron and a proton, the extra 782 keV
>> has to come from outside the electron-proton system. It cannot come from
>> the acceleration of the particles toward each other by their own
>> attraction. One simply MUST make the neutron first - even if the deuteron,
>> the end product of p+n does have a usable mass deficit.
>>
>>
>>
>> People who should know better are in denial about the rarity of p-e-p !
>>
>>
>>
>>  Let's get over it and move on.  P-e-p is dead-in-the-water for
>> adequately explaining the Rossi effect.
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>

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