In reply to Jones Beene's message of Thu, 13 Feb 2014 19:00:00 -0800: Hi Jones, [snip] >-----Original Message----- >From: mix...@bigpond.com > >>> When a gamma reaction is known to happen with the same reactant, how can >that reaction be excluded from happening, in a new scenario when both >reactions are given enough energy to overcome the fusion threshold? >Especially if one (the desired reaction) is much rarer than the other? > >> In Ed's scenario, this may be possible. Namely, if sufficient mass is lost >before the reaction occurs, such that there is insufficient remaining to >form a positron. > >Hi, > >That seems unlikely. Slight mass can perhaps be lost in ground state >collapse, but not enough. You say "mass loss before the p-e-p reaction >occurs" and the positron, which must be avoided - has .511 MeV so that means >the energy radiated by ground state collapse cannot derive from the >electron, so how is it lost from the proton? > >What mechanism is involved? > >Jones
..that's really a question that Ed should answer, as it's his theory, however I would go so far as to suggest that perhaps field cancellation by the approaching electron might do the job. However...The most energy lost through formation of a Hydrino molecule is 593 keV, slightly more than an electron mass. Creation of a deuteron via p-e-p liberates 1.44 MeV. 1.44 - 0.593 = 846 keV, which is more than enough to form a positron. Bottom line:- It seems unlikely to me that that this is the mechanism, so I'm anxious to see Ed's response. (I mention Hydrinos only because the minimum electron orbit is determined by the speed of light.) Regards, Robin van Spaandonk http://rvanspaa.freehostia.com/project.html
