What fields do you need to select. We can optimize this. On Wednesday, 30 October 2013 05:17:09 UTC-5, Diogo Munaro wrote: > > I'ts working, but it's results a WHERE JOIN and takes much more time than > JOIN sintax :( > > > 2013/10/29 Massimo Di Pierro <massimo....@gmail.com <javascript:>> > >> Try this: >> >> rows = db(db.groups.id == db.lab.group_id)(db.lab.id == >> db.researcher_lab_permission.l**ab_id)(db.researcher.id == >> db.researcher_lab_permission.r**esearcher_id)(db.researcher.us**er_id == >> db.auth_user.id).select(db.**groups.name <http://db.groups.name/>, >> db.city.name,db.**auth_user.ALL) >> >> >> On Monday, 28 October 2013 21:46:28 UTC-5, Diogo Munaro wrote: >> >>> Here is the sql generated: >>> >>> SELECT groups.name, city.name, auth_user.email, name1.id, >>> name1.is_active, name1.created_on, name1.created_by, name1.modified_on, >>> name1.modified_by, name1.user_id, name1.image, name1.image_file, >>> name1.lattes, name2.id, name2.is_active, name2.created_on, >>> name2.created_by, name2.modified_on, name2.modified_by, name2.site, >>> name2.url, name2.cnpj, name2.type_id, name2.group_id, name2.privacity FROM >>> researcher_lab_permission, researcher, lab JOIN groups ON ((groups.id = >>> lab.group_id) AND (groups.is_active = 'T')) JOIN city ON (city.id = >>> groups.city_id) JOIN auth_user ON ((researcher.user_id = auth_user.id) >>> AND (auth_user.is_active = 'T')) JOIN `researcher` AS name1 ON ( >>> researcher.id = researcher_lab_permission.**researcher_id) JOIN `lab` >>> AS name2 ON ((lab.id = researcher_lab_permission.lab_**id) AND >>> (lab.is_active = 'T')) >>> >>> Some JOINS are wrong >>> >>> >>> 2013/10/29 Diogo Munaro <diogo....@gmail.com> >>> >>>> I need these joins because I need filter some tables without selecting >>>> all the tables and filtering with where. Anyway, I tried: >>>> >>>> rows = (db.groups.id == db.lab.group_id)(db.lab.id == >>>> db.researcher_lab_permission.l**ab_id)(db.researcher.id == >>>> db.researcher_lab_permission.r**esearcher_id)(db.researcher.us**er_id >>>> == db.auth_user.id).select(db.**groups.name <http://db.groups.name/>, >>>> db.city.name,db.**auth_user.ALL) >>>> >>>> And it returns: >>>> <type 'exceptions.TypeError'> 'Query' object is not callable >>>> I'm using db.executesql and it's working: >>>> >>>> db.executesql('''SELECT l.id,g.name,c.name FROM >>>> researcher_lab_permission as rl JOIN lab as l >>>> JOIN researcher as r JOIN auth_user as a JOIN groups as >>>> g JOIN city as c >>>> ON rl.researcher_id = r.id AND rl.lab_id = l.id AND >>>> a.id = r.user_id AND l.group_id = g.id >>>> AND c.id = g.city_id WHERE a.id = %s''' >>>> %(auth.user_id)) >>>> >>>> Something strange with DAL... >>>> >>>> 2013/10/28 Massimo Di Pierro <massimo....@gmail.com> >>>> >>>>> (db.groups.**id <http://db.groups.id/> == db.lab.group_id)(db.lab.id == >>>>> db.researcher_lab_permission.**l**ab_id)(db.**researcher.id<http://db.researcher.id/> >>>>> == db.researcher_lab_permission.**r**esearcher_id)(db.researcher.**us >>>>> **er_id == >>>>> db.auth_user.id).select(db.**groups.name<http://db.groups.name/> >>>>> ,db.**city.name <http://db.city.name/>,db.**auth_user.ALL) >>>> >>>> >>>> >>>> >>> -- >> Resources: >> - http://web2py.com >> - http://web2py.com/book (Documentation) >> - http://github.com/web2py/web2py (Source code) >> - https://code.google.com/p/web2py/issues/list (Report Issues) >> --- >> You received this message because you are subscribed to a topic in the >> Google Groups "web2py-users" group. >> To unsubscribe from this topic, visit >> https://groups.google.com/d/topic/web2py/0YdtJwCEdl4/unsubscribe. >> To unsubscribe from this group and all its topics, send an email to >> web2py+un...@googlegroups.com <javascript:>. >> For more options, visit https://groups.google.com/groups/opt_out. >> > >
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