On 23/07/2010, at 7:42 AM, Chuck Hill wrote:

>>> How are you modeling these relationships?
>> 
>> Originally, just this: a mandatory, to-one relationship from A to B.  
>> Consider it to be a parent (B) with optional child (A).  Every child has a 
>> parent (hence the current mandatory to-one from A to B), and every parent 
>> has zero or one child.  So I've tacked on an optional to-one relationship 
>> from B to A to model the latter.  I take it there's no way to convince EOF 
>> that these relationships are inverses, and get the convenience of updating 
>> both sides of the relationship at the same time.
> 
> Where are the FKs?  B hold's A's PK as an FK?

Yes, and vice versa.  Only difference is that B to A is optional (parent can 
have zero children), A to B is mandatory (child must have a parent).

> They both have the same PK?

No.  (Would this help?)


-- 
Paul.

http://logicsquad.net/


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