> On Apr 11, 2021, at 8:30 PM, Andy Durbin <a.dur...@msn.com> wrote:
> 
> This seems to imply that the noise being considered is the noise in the 
> actual receiver passband and not the total noise in a 2.5 kHz bandwidth.

Andy - How is the program going to consider a frequency that isn’t being passed 
to it from the receiver?  If the receiver can’t hear it because it is narrowed 
down, where does it come from?

Gary - AG0N

_______________________________________________
wsjt-devel mailing list
wsjt-devel@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/wsjt-devel

Reply via email to